admin

2 months ago

Guest #9847967

2 months ago

technically you could write 60km/1.5hr but I think you meant km/hr.

So your traveling 60km every 1.5hours but you only want to know how much every one hour. think of 1.5 as 150% of what you want (which is one) take 60 divide it into one hundred pieces (60/150) then multiply buy 100% of what you want (quotient of last problem * 100)

final equation looks like this (60/150) 100 = 40 km/ hr

Ps. *=multiply

So your traveling 60km every 1.5hours but you only want to know how much every one hour. think of 1.5 as 150% of what you want (which is one) take 60 divide it into one hundred pieces (60/150) then multiply buy 100% of what you want (quotient of last problem * 100)

final equation looks like this (60/150) 100 = 40 km/ hr

Ps. *=multiply

Guest #9847968

2 months ago

Your average speed is 60 km per 1.5 hours. In a somewhat more popular unit, it's 60/1.5=40 km/hr.

Question

f(x)={1/2x-2, if xâ‰¥0}

Â Â Â Â Â {3/4x+3, if x<0}

Graph this equation?

I don't understand how to do this.

Â Â Â Â Â {3/4x+3, if x<0}

Graph this equation?

I don't understand how to do this.

Solution 1

[tex]f(x)= \left\{\begin{array}{ccc}\frac{1}{2}x-2&if\ x\geq0\\\frac{3}{4}x+3&if\ x < 0\end{array}\right\\------------------\\x < 0\to f(x)=\frac{3}{4}x+3\\\\for\ x=-4\to y=\frac{3}{4}(-4)+3=-3+3=0\to(-4;\ 0)\\for\ x=0\to y=\frac{3}{4}(0)+3=3\to(0;\ 3)\\------------------------\\x\geq0\to f(x)=\frac{1}{2}x-2\\\\for\ x=0\to y=\frac{1}{2}(0)-2=-2\to(0;-2)\\for\ x=4\to y=\frac{1}{2}(4)-2=2-2=0\to(4;\ 0)\\------------------------------\\Look\ at\ the\ picture.[/tex]

Question

* Use for question 4-6 *

The expression 16t2 models the distance in feet that an object falls during t seconds after being dropped. Find the distance an object falls during each time.

4) .25 sec 5) .5 sec 6) 2 sec

need helpp

The expression 16t2 models the distance in feet that an object falls during t seconds after being dropped. Find the distance an object falls during each time.

4) .25 sec 5) .5 sec 6) 2 sec

need helpp

Solution 1

16ft.(.25s)2

4ft/s*2

8ft/s

16ft(.5s)2

8ft/s * 2

16ft/s

16ft(2s)2

32ft/s * 2

64ft/s

ft =feet

s =second(s)

/ =per

4ft/s*2

8ft/s

16ft(.5s)2

8ft/s * 2

16ft/s

16ft(2s)2

32ft/s * 2

64ft/s

ft =feet

s =second(s)

/ =per

Question

Round 157 to the nearest ten

Solution 1

160

because 157 is closer to 160 than 150

because 157 is closer to 160 than 150

Solution 2

If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up (+1).

If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).

**15****7**** â‰ˆ**** 160**

If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).

Question

Solve for x 3(8x-5)=-4(7-6x)

Solution 1

3(8x - 5) = -4(7 - 6x)

Distribute 3 and -4 inside their respective parentheses.

24x - 15 = -28 + 24x

Add 28 to both sides.

24x + 13 = 24x

Subtract 24x from both sides.

13 = 0

This is an untrue statement, so that means there are no solutions to this equation.

Your answer is **no solution.**

Solution 2

**Answer: **

no solution

**Step-by-step explanation:**

I did this question on my homework and I got it correct

Hope this helps! ;)

Question

Â Find the midpoint of the segment joining the points: (4, -2) and (-8, 6) Hint: Formula for midpoint is (x1+x2)/2, (y1+y2)/2Â

Solution 1

[tex](4;-2);\ (-8;\ 6)\\\\the\ midpoint:\left(\frac{4+(-8)}{2};\ \frac{-2+6}{2}\right)\to\left(\frac{4-8}{2};\ \frac{4}{2}\right)\to\left(\frac{-4}{2};\ \frac{4}{2}\right)\to(-2;\ 2)[/tex]

Solution 2

**Answer:**

(-2, 2)

**Step-by-step explanation:**

Look at the image down below!! (ï¾‰â—•ãƒ®â—•)ï¾‰*:ï½¥ï¾Ÿâœ§

Question

What is negative five over eight -5/8 b = 10

Solution 1

[tex]- \frac{5}{8}\cdot b = 10 \ \ \ |multiply\ both\ sides\ by\ (-\frac{8}{5}) \\\\(-\frac{8}{5})\cdot (- \frac{5}{8})\cdot b =(-\frac{8}{5})\cdot 10\\\\b=(-8)\cdot 2\\\\b=-16[/tex]

Question

solve and reduce to lowest term 5 1/2- 2/3

Solution 1

[tex]5 \frac{1}{2}- \frac{2}{3}= 5 \frac{3}{6}- \frac{4}{6}=4\frac{9}{6}-\frac{4}{6}=4\frac{5}{6}[/tex]

Solution 2

5 1/2 - 2/3

11/2 - 2/3

33/6 - 4/6

29/6

11/2 - 2/3

33/6 - 4/6

29/6

Question

Use expressions for odd integers to confirm the conjecture that the product for two odd integers is an odd integer.

Solution 1

2n + 1 Â et 2n + 3 are two odd integers with n integer

(2n+1)(2n+3) = 4nÂ² + 8n + 3 =2(4nÂ² + 4n) + 3Â

2(4nÂ² + 4n) is an even integer soÂ 2(4nÂ² + 4n) +Â 3 is an odd numberÂ

because the sum of an even number and an odd number is an odd number.

(2n+1)(2n+3) = 4nÂ² + 8n + 3 =2(4nÂ² + 4n) + 3Â

2(4nÂ² + 4n) is an even integer soÂ 2(4nÂ² + 4n) +Â 3 is an odd numberÂ

because the sum of an even number and an odd number is an odd number.

Question

What is the answer to this problem and how do you solve it -6=b/18

Solution 1

[tex]-6=\frac{b}{18} \ \ | \ multiply\ both\ sides\ by\ 18\\\\18\cdot (-6)=18\cdot \frac{b}{18}\\\\ 108=b[/tex]

Question

How do I solve 2x+y=10

Solution 1

[tex]2x+y=10\ \ | \ subtract\ 2x\ to\ both\ sides \\\\y=-2x +10\\\\ is \ a \ linear \ equation\\\\The \ graph \ of \ \ y= - 2x +10 \ \ is \ a \ straight \ line. \\\\slope: \ m=-2 \\y-intercept: \ b=10[/tex]

[tex]x=0\ \to \ \ y= - 2x +10=-2\cdot 0+10=0+10=10\\\\x=5\ \to \ \ y= - 2x +10=-2\cdot 5+10=-10+10= 0[/tex]

Â

[tex]x=0\ \to \ \ y= - 2x +10=-2\cdot 0+10=0+10=10\\\\x=5\ \to \ \ y= - 2x +10=-2\cdot 5+10=-10+10= 0[/tex]

Â

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