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X 13 16 18 21 23 25 26 31 p(x) .07 .21 .17 .25 .05 .04 .13 .08 the mean

X 13 16 18 21 23 25 26 31 p(x) .07 .21 .17 .25 .05 .04 .13 .08 the mean of the discrete random value variable x is the 20.59. What is the variance of X? Round your answer to the nearest hundredth a 27.89 b27.89 c33.15 d23.18

2 months ago

Solution 1

Guest Guest #5717
2 months ago
First compute the second moment:

\mathbb E[X^2]=\displaystyle\sum_x x^2p(x)=13^2\cdot0.07+\cdots+31^2\cdot0.08\approx447.13

Then the variance of X is

\mathbb V[X]=\mathbb E[X^2]-\mathbb E[X]^2\approx447.13-20.59^2\approx23.18

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Learn more about semiannual interest method here:-brainly.com/question/15069646

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