When the pressure that a gas exerts on a sealed container changes from

When the pressure that a gas exerts on a sealed container changes from 22.5 psi to psi the temperature changes from 110 c to 65.0 c

2 months ago

Solution 1

Guest Guest #7443
2 months ago
Gay- Lussacs law states that the pressure of a gas is directly proportional to temperature for a fixed amount of gas at constant volume.
therefore P/T = k
where P - pressure , T - temperature and k - constant 
 \frac{P1}{T1} =  \frac{P2}{T2}

parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
T1 - temperature in kelvin - 110 °C + 273 = 383 K
T2 - 65.0 °C + 273 = 338 K
substituting these values in the equation 

 \frac{22.5 psi}{383 K} =  \frac{P}{338K}
P = 19.9 psi 
new pressure is 19.9 psi

Solution 2

Guest Guest #7444
2 months ago

Answer:

19.9 psi

Explanation:

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Learn more:

1. Which sample is a pure substance? brainly.com/question/2227438

2. Which is a characteristic of a  mixture? brainly.com/question/1917079

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Matter in our surroundings

Keywords: liquid, gas, solid, states of matter, intermolecular forces, shape, volume, matter, strong, weakest, motion of particles.

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Answer:

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