3.5 * 10^6
In this question, we are asked to calculate the the k-value for the reaction of HOCl with OH- given Ka value for HOCl
Firstly, we write the dissociation equation for HOCl
This is as follows;
HOCl ——> H+ + OCl-
Now, we write an expression for Ka
Ka = [H+][OCl-]/HOCl = 3.5 * 10^-8
Now, we write an equation for the reaction of HOCl and OH- ;
HOCl + OH- —-> OCl- + H2O(l)
The K value expression for this can be written as;
K = [OCl-]/[HOCl][OH-]
= [H+][OCl-]/[HOCl] * [1/[H+][OH-]
= ka * 1/Kw = 3.5 * 10^-8 /(1 * 10^-14) = 3.5 * 10^6
The changes that occur during electron capture are the mass number is unchanged and the atomic number decreases. The correct option is C.
Electron capture is a process when the electrons of the inner orbital of an atom, are captured but the nucleus and the emission of neutrino happens, and the protons are changed into neutrons.
In electron capture, the element changes into another atom with a change in the number of the proton, usually decreasing. An example is a carbon with proton 6 changes into boron with proton 5.
Thus, the correct option is C, the mass number is unchanged and the atomic number decreases.
Learn more about electron capture, here:
The oxidation state of the Ru metal in the complex is .
The oxidation number is used to represent the formal charge on an atom. It also shows that gain or loss of electrons by the atom. Oxidation number can be a positive or negative number but cannot be fractional.
The rules to identify the oxidation state:
(1) The oxidation state of an atom in the elemental form is zero.
(2) The total charge on the species is equal to the sum of the oxidation state of individual atoms.
(3) The oxidation state of halides is -1. For example, fluorine, chlorine, bromine, iodine have -1 oxidation state.
(4)Hydrogen has a +1 oxidation state.
(5) Oxygen has an oxidation state -2.
(6) In a coordination compound, neutral ligands have zero oxidation state and negative ligands such as CN have -1 oxidation.
The given compound is
Here, CN is a negative ligand thus oxidation state is -1 and CO is a neutral ligand thus it has 0 oxidation state. Also, the complex has -1 negative charge.
The expression to calculate the oxidation state in is,
Rearrange equation (1) for the oxidation state of Ru.
Substitute -1for the oxidation of CN and 0 for the oxidation state of CO in equation (2).
The oxidation state of Ru is zero.
1. General statement that is not applied on metals: brainly.com/question/2474874
2. The neutral element represented by the excited state electronic configuration: brainly.com/question/9616334
Grade: Senior school
Chapter: Coordination complex
Keywords: Oxidation state, metal complex, ru(cn)(co)4-, formal charge, cynide, carbonyl, zero, hydrogen, oxygen, 0 and -1.
V = n·R·T / p.
V(N₂) = 1.55 mol · 0.08206 L·atm/mol·K · 273 K / 1.00 atm.
V(O₂) = 34.72 L.
Alpha decay is an emission of a ₂⁴He nucleus. After an alpha decay, the formed daughter nuclide has the reduced mass number by 4 and reduced atomic number by 2 with compared to the parent atom.
After an alpha decay of ₉₂²³⁸U, the formed daughter atom should be Th (Thorium) which has atomic number as 92 - 2 = 90. The equation is,
₉₂²³⁸U → ₉₀²²⁹Th + ₂⁴He
The sum of mass number and sum of atomic number should be equal in both side.