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What is the equation of the line that passes through the points (-1,2)

What is the equation of the line that passes through the points (-1,2) and (6,3) in slope intercept form

2 months ago

Solution 1

Guest Guest #8188
2 months ago

\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ &&(~ -1 &,& 2~) &&(~ 6 &,& 3~) \end{array} \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-2}{6-(-1)}\implies \cfrac{3-2}{6+1}\implies \cfrac{1}{7} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-2=\cfrac{1}{7}[x-(-1)]\implies y-2=\cfrac{1}{7}(x+1) \\\\\\ y-2=\cfrac{1}{7}x+\cfrac{1}{7}\implies y=\cfrac{1}{7}x+\cfrac{1}{7}+2\implies y=\cfrac{1}{7}x+\cfrac{15}{7}

Solution 2

Guest Guest #8189
2 months ago

Answer:

Step 1: Choose (x1, y1). (6,3)

Step 2: x2= -1 y2=2

Step 3: 1/7

Step 4: b= 15/7

What is the equation of the line in slope-intercept form?

B) y=1/7x+15/7

Step-by-step explanation:

The bold numbers are the answers.

( I need mo pts)

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