Find the sum of the measures of the interior angles of a 52-gon.

Find the sum of the measures of the interior angles of a 52-gon.

2 months ago

Solution 1

Guest Guest #5679
2 months ago
We know that
52-gon means a polygon having 52 sides. 
There is a formula for calculating the sum of interior angles of a polygon : 
(2n-4) x 90° or (n-2) x 180° , where 'n' = number of sides. 

Now, for sum of the interior angles of 52-gon: 
(n-2) x 180° 
=(52-2) x 180° 
=50 x 180° 

the answer is
the sum of the measures of the interior angles of a 52-gon is 9000°

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3500- 210.5 = $3289.5

So in my estimation, it is $3,318.41
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